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#### Serbinator

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Apologies if this is the wrong section but I rarely ever post - as you can probably see.

It's to do with quadratic expressions. Basically, the question is:

Express (x-3)^2 as a shape (not a graph). This can either be done as the orginal expression or expressed as x^2-6x+9.

#### Ruth

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##### Boiling ramen at 1am because life is still happeni
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Sorry man, Intermediate 2 pupil here. #### Kling Klang

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2 is greater then 1.

• HiddenViolence and Proc

#### Green Light

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##### Ex nihilo
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• ABrown and A-C-P

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#### A-C-P

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##### a Stupid Idea from Bad Creative
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Sorry dude about few (wel lactually more than a few now :lol) years ago when I took that class in college I may have been able to help you out, but I have already killed those brain cells off (they were weak)

I would go with Professor's Steiner's help as well :steiner

#### Tronnik

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I believe the answer is govno jedno.

• Johnny_XTREME

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You're much better off using google than trying to find help here.

#### RD25

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Apologies if this is the wrong section but I rarely ever post - as you can probably see.

It's to do with quadratic expressions. Basically, the question is:

Express (x-3)^2 as a shape (not a graph). This can either be done as the orginal expression or expressed as x^2-6x+9.

Maybe it's referring to the 'U' shape of the graph?

It will cross the x-axis @ -3 and +3, and by completing the square the co-ordinates of the vertex are (-3, 0) [I think] might be +3.

#### HardKoR

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Maybe it's referring to the 'U' shape of the graph?

It will cross the x-axis @ -3 and +3, and by completing the square the co-ordinates of the vertex are (-3, 0) [I think] might be +3.

A squared equation automatically denotes a parabolic function(U shaped).

y=x^2 is the basic parabola. y=x^2+a is the parabola shifted up or down a units. y=(x+b)^2 is a parabola shifted left or right b units.

Setting the original function equal to zero will yield the x-intercepts. In the case the answer is only positive 3. So for a parabola to only have one x-intercept means its vertex is at the intercept @ (3,0).

I would give credit for the following answers(or as close to)

A parabola shifted to right 3 units.

Or

A parabola whose vertex lies on the coordinate (3,0)

#### FITZ

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A squared equation automatically denotes a parabolic function(U shaped).

y=x^2 is the basic parabola. y=x^2+a is the parabola shifted up or down a units. y=(x+b)^2 is a parabola shifted left or right b units.

Setting the original function equal to zero will yield the x-intercepts. In the case the answer is only positive 3. So for a parabola to only have one x-intercept means its vertex is at the intercept @ (3,0).

I would give credit for the following answers(or as close to)

A parabola shifted to right 3 units.

Or

A parabola whose vertex lies on the coordinate (3,0)
I glanced over what you said and while it all seems to be true that's not the question. He needs to know the shape.

U

That's the shape of it basically.

And OP, literally just copy and paste the equation into google and it shows you the graph.

#### Serbinator

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Sorry for the late replies guys, but in the first post I stated I didn't need it as a graph. It was pretty simple when my teacher showed me.

I can't post an image of it because of my post count but I don't think anyone's particularly interested :lol

#### Chip

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I left school last Summer. It's just hit home how much I've forgot since leaving.

#### Phantomph

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Yep, don't use it you forget it all!

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