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It's to do with quadratic expressions. Basically, the question is:

Express (x-3)^2 as a shape (not a graph). This can either be done as the orginal expression or expressed as x^2-6x+9.

Thanks in advance.

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Joined

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58 Posts

It's to do with quadratic expressions. Basically, the question is:

Express (x-3)^2 as a shape (not a graph). This can either be done as the orginal expression or expressed as x^2-6x+9.

Thanks in advance.

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2 is greater then 1.

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9,319 Posts

Let Professor Steiner help you out

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6,868 Posts

:lmao Repped2 is greater then 1.

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Maybe it's referring to the 'U' shape of the graph?

It's to do with quadratic expressions. Basically, the question is:

Express (x-3)^2 as a shape (not a graph). This can either be done as the orginal expression or expressed as x^2-6x+9.

Thanks in advance.

It will cross the x-axis @ -3 and +3, and by completing the square the co-ordinates of the vertex are (-3, 0) [I think] might be +3.

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Pretty decent answer, I would give partial credit for that answer.Maybe it's referring to the 'U' shape of the graph?

It will cross the x-axis @ -3 and +3, and by completing the square the co-ordinates of the vertex are (-3, 0) [I think] might be +3.

A squared equation automatically denotes a parabolic function(U shaped).

y=x^2 is the basic parabola. y=x^2+a is the parabola shifted up or down

Setting the original function equal to zero will yield the x-intercepts. In the case the answer is only positive 3. So for a parabola to only have one x-intercept means its vertex is at the intercept @ (3,0).

I would give credit for the following answers(or as close to)

A parabola shifted to right 3 units.

Or

A parabola whose vertex lies on the coordinate (3,0)

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I glanced over what you said and while it all seems to be true that's not the question. He needs to know the shape.Pretty decent answer, I would give partial credit for that answer.

A squared equation automatically denotes a parabolic function(U shaped).

y=x^2 is the basic parabola. y=x^2+a is the parabola shifted up or downaunits. y=(x+b)^2 is a parabola shifted left or rightbunits.

Setting the original function equal to zero will yield the x-intercepts. In the case the answer is only positive 3. So for a parabola to only have one x-intercept means its vertex is at the intercept @ (3,0).

I would give credit for the following answers(or as close to)

A parabola shifted to right 3 units.

Or

A parabola whose vertex lies on the coordinate (3,0)

That's the shape of it basically.

And OP, literally just copy and paste the equation into google and it shows you the graph.

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I can't post an image of it because of my post count but I don't think anyone's particularly interested :lol

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